Inequalities - Revision history

A WASSERMANN at 09:57, 8 June 2017

2017-06-08T09:57:26Z

← Older revision		Revision as of 09:57, 8 June 2017
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	===The JavaScript code===		===The JavaScript code===
	<source lang="javascript">		<source lang="javascript">
	var b = JXG.JSXGraph.initBoard('box1', {boundingbox: [-5, 5, 5, -5], axis:true});		var board = JXG.JSXGraph.initBoard('box1', {boundingbox: [-5, 5, 5, -5], axis:true});
	var line1 = b.create('line', [3, 2, -1]), // Line y = 2x + 3 or 2x - 1y + 3 = 0		var line1 = board.create('line', [3, 2, -1]), // Line y = 2x + 3 or 2x - 1y + 3 = 0
	ineq1 = b.create('inequality', [line1], {fillColor: 'yellow'}); //This would plot the inequality 2x - y + 3 <= 0		ineq1 = board.create('inequality', [line1], {fillColor: 'yellow'}); //This would plot the inequality 2x - y + 3 <= 0

	var line2 = b.create('line', [-3, 1, 0], {strokeColor: 'black'}); // Line x = 3 or 1x + 0y - 3 = 0		var line2 = board.create('line', [-3, 1, 0], {strokeColor: 'black'}); // Line x = 3 or 1x + 0y - 3 = 0
	var ineq2 = b.create('inequality', [line2], {inverse: true, fillColor: 'red'}); //This would plot the inequality 1x + 0y - 3 >= 0		var ineq2 = board.create('inequality', [line2], {inverse: true, fillColor: 'red'}); //This would plot the inequality 1x + 0y - 3 >= 0
	</source>		</source>

	[[Category:Examples]]		[[Category:Examples]]
	[[Category:Calculus]]		[[Category:Calculus]]

2017-06-08T09:56:17Z

@@ Line 1: / Line 1: @@
 To graph inequalities of the "less than" form
 "ax + by + c <= 0"
 <source lang="javascript">
-var line = b.create('line', [c, b, a]),
+var line = board.create('line', [c, b, a]),
-ineq = b.create('inequality', [line]);
+ineq = board.create('inequality', [line]);
 </source>
 If one wants to show "greater than" i.e.  "ax + by + c >= 0" , ''inverse:true'' has to be used:
 <source lang="javascript">
-var line = b.create('line', [c, b, a]),
+var line = board.create('line', [c, b, a]),
-ineq = b.create('inequality', [line], {inverse:true});
+ineq = board.create('inequality', [line], {inverse:true});
 </source>

2017-06-08T09:54:44Z

@@ Line 44: / Line 44: @@
      ineq2 = b.create('inequality', [line2], {fillColor: 'yellow'});
 </source>
 [[Category:Examples]]
 [[Category:Calculus]]

2017-06-02T13:12:16Z

← Older revision		Revision as of 13:12, 2 June 2017
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	ineq = b.create('inequality', [line]),		ineq = b.create('inequality', [line]),
	</source>		</source>
	and an ~~equality~~ of this line have to be created.		and an inequality of this line have to be created.

			In case ''a = 0'', that is if the equation of the line is ''bx + c = 0'', the area of the inequality
			''bx + c <= 0'' is shown.

	If one wants to show "greater than", ''inverse:true'' has to be used:		If one wants to show "greater than", ''inverse:true'' has to be used:
	<source lang="javascript">		<source lang="javascript">
Line 16:		Line 20:
	The first, black line has the equation ''y = c'' or ''0 = -1y + 0x + c'',		The first, black line has the equation ''y = c'' or ''0 = -1y + 0x + c'',
	the second, blue line has the equation ''y = 2/3 x + 1'' or ''0 = -3y + 2x +1''.		the second, blue line has the equation ''y = 2/3 x + 1'' or ''0 = -3y + 2x +1''.

	~~In case ''a = 0'', that is if the equation of the line is ''bx + c = 0'', the area of the inequality~~
	~~''bx + c <= 0'' is shown.~~

	<jsxgraph width="400" height="400" box="box1">		<jsxgraph width="400" height="400" box="box1">

2017-06-02T13:11:20Z

← Older revision		Revision as of 13:11, 2 June 2017
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	The first, black line has the equation ''y = c'' or ''0 = -1y + 0x + c'',		The first, black line has the equation ''y = c'' or ''0 = -1y + 0x + c'',
	the second, blue line has the equation ''y = 2/3 x + 1'' or ''0 = -3y + 2x +1''.		the second, blue line has the equation ''y = 2/3 x + 1'' or ''0 = -3y + 2x +1''.

			In case ''a = 0'', that is if the equation of the line is ''bx + c = 0'', the area of the inequality
			''bx + c <= 0'' is shown.

	<jsxgraph width="400" height="400" box="box1">		<jsxgraph width="400" height="400" box="box1">

2017-06-02T13:06:16Z

← Older revision		Revision as of 13:06, 2 June 2017
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	To graph inequalities of the form		To graph inequalities of the form
	''y <= b/a ~~\cdot~~ x + c''		''y <= b/a * x + c/a''
	a line of the form		a line of the form
	<source lang="javascript">		<source lang="javascript">

2017-06-02T13:05:07Z

← Older revision		Revision as of 13:05, 2 June 2017
Line 1:		Line 1:
	To graph inequalities of the form		To graph inequalities of the form
	''~~ay + bx~~ + c ~~<= 0~~''		''y <= b/a \cdot x + c''
	a line of the form		a line of the form
	<source lang="javascript">		<source lang="javascript">

2014-12-16T13:06:44Z

← Older revision		Revision as of 13:06, 16 December 2014
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	In the following example, two lines are shown.		In the following example, two lines are shown.
	The first, black line has the equation ''y = c'' or ''0 = -1y + 0x + c'',		The first, black line has the equation ''y = c'' or ''0 = -1y + 0x + c'',
	the second, blue line has the equation ''y = 2/3 x + 1'' or ''0 = -3y + 2x +1''		the second, blue line has the equation ''y = 2/3 x + 1'' or ''0 = -3y + 2x +1''.

	<jsxgraph width="400" height="400" box="box1">		<jsxgraph width="400" height="400" box="box1">

2014-12-16T13:06:21Z

← Older revision		Revision as of 13:06, 16 December 2014
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	</source>		</source>

			In the following example, two lines are shown.
			The first, black line has the equation ''y = c'' or ''0 = -1y + 0x + c'',
			the second, blue line has the equation ''y = 2/3 x + 1'' or ''0 = -3y + 2x +1''

	<jsxgraph width="400" height="400" box="box1">		<jsxgraph width="400" height="400" box="box1">

2014-12-16T13:03:52Z

← Older revision		Revision as of 13:03, 16 December 2014
Line 1:		Line 1:
	To graph inequalities of the form		To graph inequalities of the form
	~~:<math>~~ ay + bx + c <= 0 ~~</math>~~		''ay + bx + c <= 0''
	a line of the form		a line of the form
	<source lang="javascript">		<source lang="javascript">